1^(1+d)=6

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Solution for 1^(1+d)=6 equation: 



1^(1+d)=6

We move all terms to the left:

1^(1+d)-(6)=0

We add all the numbers together, and all the variables

1^(d+1)-6=0

We move all terms containing d to the left, all other terms to the right

1^(d+1)=6

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